×
Skip to content

Motorola BLN1228A34 1E53M Circuit Board with Chips

Have a product question? Ask a question

FREE Returns

This item is Haloid Guaranteed and includes a 3-month warranty. Learn more about Haloid Guaranteed.

Description:

  • Manufacturer: MOTOROLA
  • Model: BLN1228A34
  • Part #: BLN1228A34

    Description:
  • These were uninstalled and extra components from a radio system we purchased.
  • Includes multiple chips including Motorola 1E53M, PC404E3, FCU9645, 5191058C01, and others
  • This items includes a 90-day warranty from Haloid.
  • Estimated Value
    Original price $999.00
    Original price $999.00 - Original price $999.00
    Original price $999.00
    Current price $299.95
    $299.95 - $299.95
    Current price $299.95
    You Save: $699.05(70%)

    FREE Returns

    No restocking fees for 30 days.

    You can return this item in unused condition and we won’t charge a restocking fee. Learn more about our returns.

    FREE shipping over $199

    Tax charged in New York only

    We collect sales tax for New York orders only. If you are exempt from NY tax, please contact us to request an exemption.
    Manufacturer: Motorola
    SKU: BLN1228A34

    1 In Stock

    Actual inventory in Haloid's warehouse.
    Quantity:
    Trust Guard Security Scanned Secure transaction

    Your transaction is secure - guaranteed.


    We guarantee that your transaction will be 100% safe. Our payment platform uses military-grade encryption and is approved by VISA, American Express, and others And we don’t share or sell your information to others. Learn more about our commitment to you.

    Low Price Guarantee

    If you purchase an item from Haloid, and find a competitor offering it online at a lower final price, then we will match the price, refund you the difference, AND beat the price by 10%!


    Learn more about our Guarantee.

    With PRO Rewards, you’ll earn $14.99 with your purchase.

    Questions & Answers

    Have a Question?

    Be the first to ask a question about this.

    Ask a Question